The topic for today is quadratic functions. Like yesterday with linear functions, I'm not sure that there is anything here that is new or particularly difficult. I walked through the use of the calculator for finding the equation of a parabola given three points (using the QuadReg feature). Other than that, students seemed very comfortable with today's concepts.
The one tricky thing I did was to write a problem with the x's and y's switched. I think it's good practice to be able to work problems with vertically or horizontally oriented parabolas.
Here are my notes for today.
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