Sunday, October 25, 2009
Welcome (back) to the PreCal Blog
So I have finally sent out author invitations. In class on Monday, we will talk about responding and signing up and your once-every-forty-two-days responsibility of posting to the blog.
Saturday, September 19, 2009
September 17/18 - Function Transformations
We spent time in class on each of Thursday and Friday talking about the more challenging function graphs that I posed on Wednesday. Those graphs were:
The main idea I want students to get from this activity is that you can always generate points on the "new" graph you are trying to draw by using appropriate points from the "old" (original) graph. The challenge is often in deciding which points to use and how many points to use.
Rather than posting my notes from class here, I have posted a file on my website that contains images of the graphs above.
On Friday in class, I handed out a copy of the first test from last year. Your test on Tuesday will be similarly constructed.
- y = v(|x|)
- y = v([|x|])
- y = [|v(x)|]
- y = v(1/x)
The main idea I want students to get from this activity is that you can always generate points on the "new" graph you are trying to draw by using appropriate points from the "old" (original) graph. The challenge is often in deciding which points to use and how many points to use.
Rather than posting my notes from class here, I have posted a file on my website that contains images of the graphs above.
On Friday in class, I handed out a copy of the first test from last year. Your test on Tuesday will be similarly constructed.
Wednesday, September 16, 2009
September 16 - Function Transformations (Challenging)
Yesterday (Tuesday, Sept 15) and today, we have been reviewing the basic transformations (up, down, left, and right shifts, reflections, stretches and shrinks). In the homework, Tuesday night, I introduced some function composition (using x^2, |x|, 1/x, and Sqrt(x)).
Today in class, after reviewing the homework, students were put in groups and given a single graph to work on. Tomorrow in class, each group will present their graph and explain how they came up with it, hopefully convincing the rest of the class that they are correct.
This is a challenging exercise. I hope that you start to understand how to generate a graph of this sort, but it may take some time and practice.
There are no notes for yesterday or today.
Today in class, after reviewing the homework, students were put in groups and given a single graph to work on. Tomorrow in class, each group will present their graph and explain how they came up with it, hopefully convincing the rest of the class that they are correct.
This is a challenging exercise. I hope that you start to understand how to generate a graph of this sort, but it may take some time and practice.
There are no notes for yesterday or today.
Monday, September 14, 2009
September 14 - Function Transformations
We started class today with a clip from comedian Brian Regan about calling up UPS to pick up some boxes. This may or may not help you remember the definition of girth.
We worked a couple problems from Friday's homework. I hope that students see the details involved in describing the inverse of a given function, especially with regard to domain issues.
I presented one six-part question as a review of the ideas of function transformations. Here it is:
Given (4, 1) is a point on the graph of y = f(x), determine a point on each of the following graphs: (note the answers are in red...)
We worked a couple problems from Friday's homework. I hope that students see the details involved in describing the inverse of a given function, especially with regard to domain issues.
I presented one six-part question as a review of the ideas of function transformations. Here it is:
Given (4, 1) is a point on the graph of y = f(x), determine a point on each of the following graphs: (note the answers are in red...)
- y = f(x) + 6 (graph moves up 6, so (4, 7))
- y = f(x – 6) (graph moves right 6, so (10, 7))
- y = f(6x) (horizontal shrink, so (2/3, 1))
- y= 6f(x) (vertical stretch, so (4, 6))
- y = Sqrt(f(x)) (similar to #4, only the y value is affected (and since Sqrt(1) = 1), the answer is (4, 1))
- y = f(Sqrt(x)) (similar to #3, only the x value is affected, so the answer is (16, 1))
September 11 - Inverse functions
The topic for today was inverse functions.
The inverse of a given function, f(x), is derived by taking the order pairs that make up f(x) and switching the inputs and outputs. So if (a, b) is a point on f(x), then (b, a) is a point on the inverse of f(x).
Note the inverse of a function might not be a function. No biggie.
(notes for Friday)
The inverse of a given function, f(x), is derived by taking the order pairs that make up f(x) and switching the inputs and outputs. So if (a, b) is a point on f(x), then (b, a) is a point on the inverse of f(x).
Note the inverse of a function might not be a function. No biggie.
(notes for Friday)
Thursday, September 10, 2009
Sept 10 - Function Operations (including Composition)
We had a quiz in class today. The bonus was a bit of a fiasco for my 6th period class - but I have a solution for that - I'll talk about it in class tomorrow.
Function composition is simply the operation of substituting one function into another one. If we have two functions f(x) and g(x), I can write f(g(x)) ("f of g of x") or g(f(x)) ("g of f of x"). Generally speaking, they will not be the same (function composition is not commutative). A couple of the problems may be tricky because you have to determine the output of the function from a graph, not a formula.
My notes for today are brief.
Function composition is simply the operation of substituting one function into another one. If we have two functions f(x) and g(x), I can write f(g(x)) ("f of g of x") or g(f(x)) ("g of f of x"). Generally speaking, they will not be the same (function composition is not commutative). A couple of the problems may be tricky because you have to determine the output of the function from a graph, not a formula.
My notes for today are brief.
Wednesday, September 9, 2009
Sept 9 - Functions with Restricted Domains
Today's topic is a favorite of mine. I like these types of problems for where we are in class because they draw on a number of different topics. The main concept is graphing a function (without using a calculator) by using knowledge of parent functions and transformations. Then you'll have to analyze the graph to determine the range.
I'm posting the examples from class. The quiz tomorrow will be a couple of problems like these examples or like the homework problems.
I'm posting the examples from class. The quiz tomorrow will be a couple of problems like these examples or like the homework problems.
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